There are 3 ways of writing a remainder: with an R, as a fraction, and as a decimal. For example, 821 divided by 4 would be written as 205 R 1 in the first case, 205 1 / 4 in the second, and 205.25 in the third. The 1.0-liter Focus is rated at a humble 123 hp and 125 lb-ft of torque, and real-world output feels even weaker. Flooring the accelerator is often required to keep up with traffic. How to use the parabola equation calculator: an example. Enter the coefficients a, b and c of the standard form of your quadratic equation. Let's assume that the equation is y = 2x² + 3x - 4, what means that a = 2, b = 3 and c = -4.
- Finer Focus 1 3 Equals 0
- Finer Focus 1 3 Equals 3 4
- Finer Focus 1 3 Equals How Many Ounces
- Finer Focus 1 3 Equals A Pound
- 1/3 Equals What Percent
- Fine focus definition in the English Cobuild dictionary for learners, fine focus meaning explained, see also 'fine',fine art',fine print',fine tooth comb', English vocabulary.
- Probably the most well-known camera move, zooming gives the impression of moving closer or further away from the subject. It can be used effectively to magnify a certain focus point in the frame, but other moves such as a dolly, are a more natural way to show movement.
Diverging from reliability statistics for a post or two, let's consider one way which R(t), reliability at time, t, is useful during the design phase of a product. Apportionment is the breakdown or allocation of reliability goals or objectives to elements within the product.
Overall, the product's reliability is just one number, and it represents what the customer will experience with the product. During design, we often work on subsystems and components. Having a meaningful way to describe the reliability requirements that also assists the team to meet the overall product goal, is, well, useful.
With one client, I was requested to assist in the improvement of their current 50% field failure rate. During the day's discussions with a variety of design engineers, I found that each of the major subsystems had been designed to meet the system goal. For example, the product reliability goal was 95% at one year.
Each major subsystem and component (10 altogether) were designed, specified or procured with the idea that they each had to only meet the 95% reliability at 1-year goal. And, the team was rather successful at meeting the assumed goals for the major subsystems and components.
A quick calculation to determine the product reliability given each of the ten elements has 95% reliability shows they should expect a 60% reliability at 1 year. They were doing a bit worse than their designed reliability.
The main circuit board designer literally said, that since the board met the goal of 95%, it was good enough. If the underlying assumption that all the other elements of the product would be perfect, this team's approach would work. Unfortunately, as in many products, if any one element fails, the product fails. And, every element of a product has a finite possibility of failing.
Therefore, let's create a model that permits us to allocate reliability to each element using the series reliability model of the system. Graphically a series system is portrayed, for example, as
where each block represents an element of the system. And, if anyone block fails the ‘flow' is interrupted with no alternative path to provide the intended function.
'Weakest link' comes to mind, as a series system is only as strong as the weakest element, much like a chain.
Mathematically, a series system model of reliability is
where the product of the individual elements is the system reliability. One feature of this formula is all of the elements have to have a higher reliability than the system. Keep in mind that reliability is a probability between zero and one and considering that everything has a finite possibility of failure. And, considering when multiplying two numbers between zero and one, say 0.9 and 0.8. The result is less than the lowest number, never higher. In this case, the product of 0.9, 0.85 and 0.8 is 0.612.
This means that each element of a product should have a higher reliability than the product reliability goal. Apportionment of the reliability to the elements is one way to determine (or set) goals, objectives, or a budget for the individual elements. Minecraft folder location.
According to Ireson, Coombs, and Moss in the Handbook of Reliability Engineering and Management, 2nd edition, there are six basic ways to reasonably and non-controversially perform the task of apportionment. Adobe illustrator cc 2018. In this post, let's explore two: simple apportionment and equal apportionment.
Simple Apportionment
where, R(t) is the reliability of the system (or product) at time, t.
and, i = individual subsystems, i = 1, 2, 3, …, n.
Determine reliability estimates for the n subsystems via past product field return analysis, in-house testing, vendor information, databases, or engineering judgment. A common practice is to buffer the apportionment for the unknown or new risks in the design. Thus, by adding more element, we reserve 10 percent of the overall goal for the uncertain or unknown element's apportionment. Of course, this number can be higher or lower depending on local practice and degree of reliability risk.
Let's explore a simple example. Let's say for the holidays our rich uncle installed a new home entertainment system at our house (cool!). It has three basic elements: big screen TV, Blu-ray player, and a sound system.
Graphically this would be illustrated:
If any one part of the system doesn't work, we're not going to be able to watch the new Blu-ray movie (also provide by that wonderful uncle).
Having worked in the industry, we have some estimates of the reliability values for the various subsystems. We do not need to include every cable, yet making sure they are properly connected would be a good idea. So, let's assume we know the following for the expected reliability at one year:
1. Big screen TV's — 98%
2. Blu-ray player — 97%
3. Sound System — 98.5%
No elements are in parallel, and our highly alert ear can tell if the surround sound is working or not. We have a series system reliability speaking. The product of the three reliability provides the system reliability.
I should mention that our goal, personally speaking, is that system should never fail, or a goal of 100%. Professionally speaking, and knowing the everything has a chance of failing, a realistic goal might be 95% at one year.
Back to our estimates. The product of the three subsystem reliabilities provides a calculated system reliability.
And comparing to our goal, find that we should expect more failures (or a failure is more likely) than expected for acceptable performance. Something needs improvement and the most likely area to focus is the 'weakest link' or the Blu-ray player. Switch to a DVD player with reliability at one year of 99% or find a more reliable model, etc. Immediately we see the benefit of doing reliability apportionment – it provides a comparison to what is known and provides a focus for improvements.
Equal Apportionment
This is simple and generates the needed conversation and behavior. Every element is assigned the same apportionment. Mathematically this is represented for a system of N elements by
where R1 = R2 = … Rn, basically all elements have the same value.
Given a system goal, say 95% at one year, we can determine the individual element equal apportioned reliability goal by determining the value raised the number of elements power that equals the reliability goal.
One could also find this iteratively using Excel or a calculator knowing that the element reliability is higher than the system reliability. Following the example from above, where the system reliability goal is 95% at one year, we would solve for Re when raised to the third power equals 95%.
Thus, when every element is at least 98.32% reliable at one year, the system would be at least 95% reliable at one year.
At this point, the power supply team raised an objection knowing that they are a much more difficult element of the product than the keyboard (using a computer example). Which is true and not accounted for in this method. Yet, consider the objective and justification — and more importantly the ensuing discussion.
Back to the discussion and behavior that I mentioned earlier; in a real situation, without any reasonable prior history, working with a team to perform apportionment, we used this method.
Related:
Reliability Allocations (article)
Reliability Block Diagrams Overview and Value (article)
System Engineering and Reliability (article)
Finer Focus 1 3 Equals 0
Also published on Medium.
A parabola is set of all points in a plane which are an equal distance away from a given point and given line. The point is called the focus of the parabola and the line is called the directrix.
The focus lies on the axis of symmetry of the parabola.
Finding the focus of a parabola given its equation
If you have the equation of a parabola in vertex form y=a(x−h)2+k, then the vertex is at (h,k) and the focus is (h,k+14a).
Finer Focus 1 3 Equals 3 4
Notice that here we are working with a parabola with a vertical axis of symmetry, so the x-coordinate of the focus is the same as the x-coordinate of the vertex.
Example 1:
Finer Focus 1 3 Equals How Many Ounces
Find the focus of the parabola y=18x2.
Here h=0and k=0, so the vertex is at the origin. The coordinates of the focus are (h,k+14a) or (0,0+14a).
Since a=18, we have Xilisoft audio converter pro 6 5 3.
Casino game where you roll dice. 14a=1(12)
=2
The focus is at (0,2). N verlore verstand 1 2 download free.
Example 2:
where R1 = R2 = … Rn, basically all elements have the same value.
Given a system goal, say 95% at one year, we can determine the individual element equal apportioned reliability goal by determining the value raised the number of elements power that equals the reliability goal.
One could also find this iteratively using Excel or a calculator knowing that the element reliability is higher than the system reliability. Following the example from above, where the system reliability goal is 95% at one year, we would solve for Re when raised to the third power equals 95%.
Thus, when every element is at least 98.32% reliable at one year, the system would be at least 95% reliable at one year.
At this point, the power supply team raised an objection knowing that they are a much more difficult element of the product than the keyboard (using a computer example). Which is true and not accounted for in this method. Yet, consider the objective and justification — and more importantly the ensuing discussion.
Back to the discussion and behavior that I mentioned earlier; in a real situation, without any reasonable prior history, working with a team to perform apportionment, we used this method.
Related:
Reliability Allocations (article)
Reliability Block Diagrams Overview and Value (article)
System Engineering and Reliability (article)
Finer Focus 1 3 Equals 0
Also published on Medium.
A parabola is set of all points in a plane which are an equal distance away from a given point and given line. The point is called the focus of the parabola and the line is called the directrix.
The focus lies on the axis of symmetry of the parabola.
Finding the focus of a parabola given its equation
If you have the equation of a parabola in vertex form y=a(x−h)2+k, then the vertex is at (h,k) and the focus is (h,k+14a).
Finer Focus 1 3 Equals 3 4
Notice that here we are working with a parabola with a vertical axis of symmetry, so the x-coordinate of the focus is the same as the x-coordinate of the vertex.
Example 1:
Finer Focus 1 3 Equals How Many Ounces
Find the focus of the parabola y=18x2.
Here h=0and k=0, so the vertex is at the origin. The coordinates of the focus are (h,k+14a) or (0,0+14a).
Since a=18, we have Xilisoft audio converter pro 6 5 3.
Casino game where you roll dice. 14a=1(12)
=2
The focus is at (0,2). N verlore verstand 1 2 download free.
Example 2:
Stuffit deluxe 15 0 4. Find the focus of the parabola y=−(x−3)2−2.
Here h=3 and k=−2, so the vertex is at (3,−2). The coordinates of the focus are (h,k+14a) or (3,−2+14a).
Finer Focus 1 3 Equals A Pound
Here a=−1, so
−2+14a=−2−14
1/3 Equals What Percent
=−2.25
The focus is at (3,−2.25).
